Question

a body is falling freely under gravity. how much distance it falls during an interval of time between 1st and 2nd second of its motion?​

Answer 1

Answer:

Explanation:

S = ut + 1/2gt^2

Here, u = 0 and g = 10

Total distance covered in two seconds -

S2 =| 0 * 2 + 1/2 (-10) 2^2 | = 20 m .

Total distance covered in one second -

S1 = | 0*1 + 1/2 ( -10) 1^2 | = 5 m .

=> Distance covered by body during an interval of time between first and second seconds of its motion = (S2 - S1 ) = 20–5 = 15m .

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Answer 2

Explanation:

when ever a object falls under the influence of gravity alone it is said to be free fall