Question

A body is falling freely under gravity . how much distance it fall during an interval of time between 1st and 2nd seconds of its motion , Taking g= 10?

Answer 1

D=1/2 a t^2

a = 10 g0 = 98.1 m/s2

1/2 a = 49.05

D(1) = 49.05 * 1^2 = 49.05

D(2) = 49.05 * 2^2 = 196.20

deltaD(2,1)= 196.20 - 49.05 = 147.15 m

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