a body is falling freely under gravity how much distance it falls during an interval of time between 2nd and 3rd seconds of its motion
a 5m b 15m c 20m d 25m
Answers
Answered by
10
Answer:
25 m
Explanation:
Between 2nd and 3rd seconds means 'in 3rd second'.
Using, Sₙ = u + a/2 (2n - 1)
In question,
u = 0(at rest), a = g = 10 , n = 3
Therefore,
S₃ = 0 + (10/2) [2(3) - 1]
= (5) (6 - 1)
= 25 m
Answered by
135
Given :-
- A body is falling freely under gravity.
To Find :-
- How much distance it falls during an interval of time between 2nd and 3rd seconds of its motion.
Formula Used :-
where,
- n = Time
- u = Initial velocity
- a = Acceleration
Solution :-
Given :
- Initial velocity (u) = 0 m/s
- Acceleration = 10 m/s²
- Time (n) = 3 seconds
According to the question by using the formula we get,
The distance it falls during an interval of time between 2nd and 3rd seconds of its motion is 25 m .
Hence, the correct options is option no (d) 25 m .
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