Question

a body is falling from a height x after it has fallen to a height of x/2, it will possess​

Answer 1

Explanation:

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Answer 2

Answer:

Kinetic Energy of magnitude $\frac{1}{2\\}$mgx and potential energy of the same magnitude.

Explanation:

Initially , the body is at rest with no velocity , therefore initial KE = 0

Initial PE = mgx , as it is a height of x from the earth's surface

When it falls it loses the potential and has PE =  $\frac{1}{2\\}$mgx

Since energy has to be conserved ( We can't create or destroy energy)

Loss in PE = Gain in KE

Therefore KE = mgx - $\frac{1}{2\\}$mgx  =  $\frac{1}{2\\}$mgx