a body is falling from height H it takes t1 time to reach the ground . The time taken to cover the first half of the height is
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we know that,
t = [2H/g]½
t1 = (2H/g)½
according to question
t2 = (H/g)½
now multiply and devide by 2½ to t2
we get t2 = t1/(2)½
t = [2H/g]½
t1 = (2H/g)½
according to question
t2 = (H/g)½
now multiply and devide by 2½ to t2
we get t2 = t1/(2)½
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