Question

A body is falling under gravity, then the distance covered In 1st second of its motion is

Answer 1

Answer

• Distance covered in 1 second is 5 m

Given

• A body is falling under gravity.

To Find

• Distance covered In 1st second of its motion is

Concept Used

Equation of motion

• s = ut + ¹/₂ at²

Solution

A body is falling under gravity . It must start's from rest . So ,

Initial velocity , u = 0 m/s

Time , t = 1 s

Distance , s = ? m

Acceleration due to gravity , a = g = 10 m/s²

Apply 2 nd equation of motion .

⇒ s = ut + ¹/₂ gt²

⇒ s = (0)(1) + ¹/₂ (10)(1²)

⇒ s = 5(1²)

⇒ s = 5 m

So , Distance covered in 1 second is 5 m