A body is falling with 1m/s at a height of 3m from the ground. The speed at height 2m from the ground will be?
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Answer:
(a) 4.54 m/s
Explanation:
Case 1:
Initial velocity, u= 1m/s
height ,h= 3m
we know that,
2gh = v² - u² (let g= 9.8m/s²)
=> 2×9.8×3 = v² - 1
=> 58.8 + 1 = v²
=> v = √59.8= 7.74m/s
Case 2:
considering, the height = 2m
2gh = v² - u²
=> 2×9.8×2 = (7.74)² - u²
=> 39.2 = 59.9 - u²
=> u = √20.7
=> u = 4.54 m/s
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