a body is feeling down from a height of 300 m at a height of 200 m
Answers
Answer:
height covered by the projectile from the ground
h=ut−
2
1
gt
2
h=100t−
2
1
×9.8×t
2
h=100t–4.9t
2
…(1)
Distance covered by the projectile thrown down in time t will be, since it falls down from the restu=0
300–h=
2
1
gt
2
300–(100t–4.9t
2
)=4.9t
2
…byequation(1)
300=100t,t=3s
Thus particles meet each other at 3s
Height at which particles meet
h=100t–4.9t
2
h=100×3–4.9×9
h=255.9m
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Answer:
Let a body of mass
′
m
′
placed at a height
′
h
′
above the ground, start falling down from rest.`
When the body falls from a height h to h/2, the potential energy is given as
2
mgh
.
The body covers the distance h/2 with a velocity v. We make use of the third equation of motion to obtain velocity of the body.
v
2
−u
2
=2aS
Here, u=0,a=g and S=x
v
2
−0=
2p
2gh
,thatisv
2
=gh
Kinetic energy =
2
1
mv
2
That is, K.E=
2
mgh
Hence, at height h/2 the energy possessed is half potential energy and half the kinetic energy.