Question

A body is given + 1 coulomb charge .How many electrons are added /removed from the body??​

Answer 1

n=q÷e. 1÷1.6×10^19...............

Answer 2

Answer:

=> 1C/1.6*10^-19C = 6.25*10^18

Explanation:

As the given charge is positive, it is the result of deficiency or loss of electrons

Now from Quantization of charge

Q=ne

So,the number of electrons removed are

n=Q/e= 1C/1.6*10^-19C = 6.25*10^18

Hope you find this helpful:-)