Question

A body is in motion along a straight line. As it crosses a fixed point, a stop watch is started.The body travels a distance 1.80m in first 3 seconds and 2.20 m in next 5seconds what will be the velocity at the end of 9 seconds?​

Answer 1

0.6 m/s then 0.44 m/s 4 seconds later, then V m/s 3.5 seconds later.

Acceleration is evidently (0.6 - 0.44) / 4 m/s^2 or 0.04 m/s^2 so after another 3,5 seconds the velocity 0.44 - 3.5* 0.04 m/s^2 = 0.3 m/s

Answer 2

Answer:

0.3m/s

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