Question

a body is in rest and moves with acceleration of 4m/s2. find the distance travelled in first 3 seconds

Answer 1

We are given that the initial velocity of the particle was 0 m/s because it was stationary. Also, acceleration of the body was 4 m/s². We have to find the distance travelled in the first 3 seconds.

We know,

s = ut + ½at²

where,

1. s = Distance travelled,
2. u = Initial velocity,
3. a = Acceleration &
4. t = Time taken.

Change in formula :-

s = ½at²

[Because u = 0; 0 × t = 0]

Thus, distance travelled,

s = ½(4 m/s²)(3 s)²

→ s = (2 m/s²)(9 s²)

→ s = (2 m)(9)

→ s = 18 m Ans.

Answer 2

Answer:

basically initial velocity of the body is 0 because it starts from rest now we know

a=4m/s^2, t =3 second S=?

we Know that,

S=ut+1/2 at^2 (u=0)

S=1/2 at^2

S=1/2×4×9

S=2×9

S=18 m