a body is initially at rest it undergoes One dimensional motion with constant acceleration how it is dimension depend upon time
catmat1710:
please recheck the question
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Use 2nd eq. of motion
s = ut+(1/2)at^2
as u =0
therefore it becomes
s = (1/2)at^2
exchange sides and you'll get
s = ut+(1/2)at^2
as u =0
therefore it becomes
s = (1/2)at^2
exchange sides and you'll get
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