Question

A body is initially moving at 18 km/hr and uniformly

accelerates at the rate of 5m/s² for 8 s .

Calculate -

(a.) The final velocity,

(b.) The distance covered by it from start.​

Answer 1

V=45m/s

s=200m

Explanation:

Given-

u=18km/h

a=5m/s2

t=8 sec

To Find

v&s

Solution

To find V --

1. Convert initial velocity to it's Sl unit 2. 18km/h * 5/18 = 5m/s

Now using Kinemetic equation

• v=utat

v=5+5x8 v=5+40 v=45m/s

.

To Find S--

By using Kinemetic equation-

s=ut+1/2at? s=5x8+1/2x5x8x8 S=40+160 s=200m

.

.

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Thanks