Question

a body is initially moving at 18 km p/h and uniform acceleration at one rate of 5 m/s^2 for 8 second calculate the final velocity and distance by the object

Answer 1

Explanation:

Given u = 18; a =5; t = 8;v =?

we know v = u+at

v = 18+5*8

v = 58km/hr is the final velocity.

we know

${v}^{2} - {u}^{2} = 2as$

${58}^{2} - {18}^{2} = 2 \times 5 \times s$

3040 = 10s

s = 304 kms os the distance travelled by the body

Thus is ur answer. Hope it helps u