A body is located on a wall. It's image of equal size is to be ibtained on a parallel wall with the help of a convex lens. The lens is placed at a distance d ahead of second wall. Then the required focal length will be- 1. Only d/4 2. Only d/2 3. More than d/4 and less than d/2 4. Less than d/4 (Ans is 2. But please explain the reason)
Answers
Answered by
53
By lens formula,
1/f=1/v - 1/u
I =0 and |v| = |u| =d
1/f = 1/d -(-1/d) = 2/d
.'. f = d/2
1/f=1/v - 1/u
I =0 and |v| = |u| =d
1/f = 1/d -(-1/d) = 2/d
.'. f = d/2
RehanAhmadXLX:
Thanks :-)
Answered by
20
Answer:
Explanation:
Magnification has to be 1 .....
m= v / u
1 = v / u
V =U = d
1/f = 1/v - 1/u
V=d
U= -d
f= d/2
Similar questions