Question

a body is moving along a circular path of diameter 200m it take 40 minutee to complete one round calculate the distance and displacement at the end of 2 minutes 20 seconds

Answer 1

Answer:

200m

Explanation:

Diameter of circular track (D) = 200 m

Radius of circular track (r) = 200 / 2=100 m

Time taken by the athlete for one round (t) = 40 s

Distance covered by athlete in one round (s) = 2π r

= 2 × ( 22 / 7 ) × 100

Speed of the athlete (v) = Distance / Time

= (2 × 2200) / (7 × 40)

= 4400 / 7 × 40

Therefore, Distance covered in 140 s = Speed (s) × Time(t)

= 4400 / (7 × 40) × (2 × 60 + 20)

= 4400 / (7 × 40) × 140

= 4400 × 140 /7 × 40

= 2200 m

Number of round in 40 s =1 round

Number of round in 140 s =140/40

=3 1/2

Hence, Displacement of the athlete with respect to initial position at x= xy

= Diameter of circular track

= 200 m

Answer 2

Explanation:

Time taken = 2 min 20 sec = 140 sec. Radius, r = 100 m.

In Time to complete one round = 40 sec So, Round completed in 140 sec = 140 ÷ 40 = 3.5 (three and a half) round.

Or,

distance covered = 2 x 22/7 x 100 x 3.5 = 2200 m.

At the end, the body cavers half round and will be at a distance = diameter of circle.

ie displacement = 200m.