Question

A body is moving along a straight line. At t = 0, its velocity = 0 and acceleration = 0, and thereafter it maintains the same acceleration,​

Answer 1

Answer:

When the block is just starting to slip we have,

μ

s

N=ma

⇒μ

s

mg=4m

⇒μ

s

=0.4

Now it goes on slipping till 3 seconds, therefore in 2 seconds the block's velocity changes from 2to2×(2)

2

=8m/sec

Hence, acceleration from t=1 to t=3 secs is: a

avg

=

2

8−2

=3m/s

2

Applying equation of motion

μ

k

×m×g=m×a

avg

=3m

⇒μ

k

=0.3

Answer 2

Answer:

then the acceleration is also 0m/s² and body will be at rest as it was...