Question

A body is moving along the +ve x-axis with uniform acceleration of -4 m/s2.Its velocity at x=0 is 10m/s.The time taken by the body to reach a point at x=12m is

Answer 1

Answer:

☑d = Vo×t + 0.5×t^2.

12 = 10×t + 2t^2,

2t^2 + 10t - 12 = 0.

t^2 + 5t - 6 = 0.

(t-1)(t+6) = 0,

t-1 = 0, t = 1 s✔

t+6 = 0, t = -6 ❌

✨So, t = 1 s.

☺Hope it helps....

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Answer 2

$\boxed{Explained\:Answer}$

______________________________

Given :

Uniform Acceleration = -4m/s square .

Velocity at x=0

d = Vo*t + 0.5*t^2.

12 = 10*t + 2t^2,

2t^2 + 10t - 12 = 0.

Therefore,

t^2 + 5t - 6 = 0.

so by Splitting The Middle Term Method,we get

(t-1)(t+6) = 0,

t-1 = 0, t = 1 s.

t+6 = 0,

t = -6.

Solution: t = 1 s.