Question

A body is moving at 20m/s changes its velocity to 10m/s in 2 seconds .calculate retardation

Answer 1

Answer:

5 m/s²

Explanation:

initial velocity, u = 20 m/s

final velocity, v = 10 m/s

time taken, t = 2 s

let the acceleration = a

$a = \frac{v-u}{t} = \frac{10-20}{2} =\frac{-10}{2} =-5\ m/s^2$

Hence acceleration is -5 m/s² or the retardation is 5 m/s².

(retardation is is negative acceleration.)

Answer 2

Answer:It's a question from Newtown s 1st equation of motion

Explanation:We know ,v=u+at

Now v=20m/s

u=10m/s

t=2 sec

and a=?(let a be m)

So,20=10+m×2

20-10=2m

10=2m

10/2=m

Therefore m=5

i.e. acceleration=5m/s^2.

And that's all.

Please mark me the brainliest.