A body is moving at 5m/s will its distance-time graph be flatter or stepper than that of a body moving at 3m/sec
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As the body is moving uniformly , the velocity - time graph is a straight line BC parallel to time axis , where OB=5m/s. Let OA=5s . Draw AC⊥OX so as to meet velocity - time graph at C. Distance travelled by the body in 5s, i.e .,
s= area of rectangle OACB
or s=OA×OB=5×5=25m
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