Question

A body is moving from a to b with a uniform speed of 40 m/s and return back to again 'a' on the same path with a certain speed. The average speed found to be 48 m/s. Find out the speed at which it returns back.

Answer 1

Let the returning speed be x.

Average speed= (40 + x)/2

But average speed= 48 m/s

Therefore,

(40 + x)/2. =48

40 +x= 96

x= 96- 40

= 56 m/s

Hope it helps ^_^

Answer 2

here , we see that..

we know that

average speed = tot. dist./ tot. time

using this formula solve this...

see attachment here..
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hope it will help u