Question

A body is moving from rest under constant acceleration and let S1 be the displacement in the first (p - 1) sec and S2 be the displacement in the first p sec. The displacement in (p² - p + 1)th sec will be -​

Answer 1

Explanation:

The initial velocity of body is zero, u=0

2rd equation of motion,

S=ut+1/2at²

S=1/2at² . . . . .. .(1)

The displacement in time (P−1) sec  is

S1=1/2a(P−1)². . . . .(2)

The displacement at time P sec,

S2=1/2aP². . . . . .(3)

Adding equation (2) and (3), we get

S1+S2=1/2a(2P²−2P+1). . . . . .(4)

The displacement at time (p2−P+1)nsec

S=1/2a(2P²−2P+1). . . . .(5)

From equation (4) and (5),

S=S1+S2

please make my answer brainliest

Answer 2

Answer:

The initial velocity of body is zero, u=0

2rd equation of motion,

S=ut+21at2

S=21at2. . . . . .. .(1)

The displacement in time (P−1) sec  is

S1=21a(P−1)2. . . . .(2)

The displacement at time P sec,

S2=21aP2. . . . . .(3)

Adding equation (2) and (3), we get

S1+S2=21a(2P2−2P+1). . . . . .(4)

The displacement at time (p2−P+1)nsec

S=21a(2P2−2P+1). . . . .(5)

From equation (4) and (5),

S=S1+S2

Explanation:

Give me Brainliest answer