Question

A body is moving in a circular path of radius 10 m
and its speed (v) as a function of time (t) is given
by v = 3t. where t is in s and v is in m/s. The
acceleration of body at t = 2 s is
(1) 6.7 m/s
(2) 4.7 m/s2
13) 3.7 m/s
(4) 5.7 m/s2​

Answer 1

Answer:

i think 6.7M/s think so

Answer 2

The acceleration of body at 2 sec is 3.6 m/s²            

Explanation:

Given that,

Radius = 10 m

Speed as a function of time

v = 3t    

Time t = 2 sec

We need to calculate the acceleration of body at 2 sec

Using formula of acceleration

$a_{c}=\dfrac{v^2}{r}$

Where, v = speed

r = radius

$a_{c}$ = centripetal acceleration

Put the value into the formula

$a_{c}=\dfrac{(3\times2)^2}{10}$    

$a_{c}= 3.6\ m/s^2$

Hence, The acceleration of body at 2 sec is 3.6 m/s²

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Topic : centripetal acceleration

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