Question

A body is moving in a horizontal circle with speed of 1m/s. This speed increases with a constant rate of 2m/s2. Assuming the radius of circle is 25m. The net acceleration of the body after 2s?

Answer 1

Answer:

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Answer 2

Answer:

$net\ acceleration\ =\ \sqrt{5}$

Explanation:

Given,

initial velocity, u = 1 m/s

acceleration,a = 2 $m/s^2$

time = 2 s

according to the law of motion, final velocity

v = u + at

=> v = 1 + (2) x (2)

=> v = 5 m/s

So, the final velocity of the body will be 5 m/s

radius of the circular path = 25 m

hence, angular acceleration can be give by,

$\omega\ =\ \dfrac{v^2}{r}$

               $=\ \dfrac{5^2}{25}$

               = 1 rad/s

so, the net acceleration of the body can be given by,

   $\sqrt{a^2\ +\ \omega^2}$

$=\ \sqrt{2^2\ +\ 1^2}$

$=\ \sqrt{5}$

So, the net acceleration of the body after 2 s will be $\sqrt{5}$