Question

A body is moving in a square field of side 20m calculate distance and displacement in two rounds

Answer 1

Answer:

Square field perimeter = 4* side

Distance = 4* 20m

                = 80 m

2 rounds = 2*80= 160 m

Displacement = √( 5m)²+√(5m)²

                         = √ 25m²+25m²

                         = √50 m²

                         = 7.071 m

2 rounds = 2*7.071= 14.142 m

                         

Answer 2

Given:

Length of side of field, a= 20 m

To Find:

Distance covered and displacement of body in two rounds

Solution:

We know that,

• Distance is the length of actual path covered by body

• Displacement is the shortest distance between starting and final position

• Perimeter of a square 'P' is given by

$\purple{\boxed{\bf{P=4a}}}$

where,

a is the length of side of square

$\rule{190}{1}$

Le the perimeter of given square field be P

So,

$\longrightarrow\rm{P=4a}$

$\longrightarrow\rm{P=4(20)}$

$\longrightarrow\rm{P=80\:m}$

$\rule{190}{1}$

Let the distance covered by athlete be D and displacement of athlete be d

Since, body has completed two round of square field

So,

$\longrightarrow\rm{D=2P}$

$\longrightarrow\rm{D=2(80)}$

$\longrightarrow\rm\green{D=160\:m}$

Since, after covering 2 rounds, body will return to its starting position, so final position of body is same as the starting position

Therefore,

$\longrightarrow\rm\green{d=0\:m}$

Hence, distance covered by body in two rounds is 160 m and displacement of body is 0 m.