Question

a body is moving in a straight line and it's displacement at various instant of time is given in the following table, time (s) =0, 1,2,3,4,5,6,7 , displacement (m) 2,6, 12,12, 12,18,22,24 I) total distance travelled in interval 1s to 5s, ii) average velocity in time interval 1s to 5s

Answer 1

given table :

time (s) = 0, 1, 2, 3, 4, 5, 6, 7

displacement (m) = 2, 6, 12, 12, 12, 18, 22, 24

(i) Total distance travelled in interval 1s to 5s , S = distance travelled in 1s to 2s + distance travelled in 2s to 3s + ... + distance travelled in 4s to 5s

= (12m - 6m) + (12m - 12m) + (12m - 12m) + (18m - 12m)

= 6m + 0m + 0m + 6m

= 12m

hence, total distance travelled in interval 1s to 5s is 12m.

(ii) average velocity = net displacement/total time taken

= (final position - initial position)/total time

position of body at (t = 5s) = 18m

position of body at (t = 1s) = 6m

so, final position of body is 18m and initial position of body is 6m.

now, average velocity = (18m - 6m)/(5s - 1s)

= 12m/4s

= 3 m/s

hence, average velocity in time interval 1s to 5s is 3m/s.

Answer 2

Explanation:

here is your answer hope it is helpful