a body is moving in a straight line with initial velocity 12 m/s and initial retardation 4 m/ s ^2 its retardation decreases to zero linearly in time 't' .what is the value of time ' t' ( in sec ) if the body will completley stop moving at this time?
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Answered by
10
Answer:
Explanation:the distance covered by the body in 5th second = u+a ( n-1/2)= 7+ 4 (5-1/2)
= 7+4×9/2
= 7+ 18 = 25 m
Answered by
3
Concept:
According to the Second law of motion,
v = u + at
where v and u are the initial and final velocity of the body and a is the acceleration of the body.
Given:
The initial velocity, u = 12 m/s
Acceleration, a = - 4 m/s² (As retardation is given)
Find:
The time at which the body will completely stop.
Solution:
As the body will completely stop, the velocity of the body becomes zero.
Substituting the values in the second law of motion,
v = u + at
0 = 12 - 4t
4t = 12
t = 12/4 = 3 sec
Hence, the body will completely stop moving after 3 seconds.
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