A body is moving in a straight line with uniform acceleration it covers distance of 10m and 12m in third and fourth second respectively then the initial velocity in m/sec
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A particle is moving in a straight line with initial velocity and uniform acceleration a. If the sum of the distance travelled in t
th
and (t+1)
th
seconds is 100 cm, then its velocity after t seconds, in cm/s, is
December 20, 2019avatar
Pulkit Rambo
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ANSWER
The distance travelled in n
th
second is
S
n
=u+
2
1
(2n−1)a ....(1)
So distance travelled in t
th
&(t+1)
th
second are
S
t
=u+
2
1
(2t−1)a ....(2)
S
t+1
=u+
2
1
(2t+1)a ....(3)
As per question,
S
t
+S
t+1
=100=2(u+at) ....(4)
Now from first equation of motion the velocity of particle after time t, if it moves with an acceleration a is
v=u+at ....(5)
where u is initial velocity
So from equation (4) and (5), we get v=50cm/s
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