Question

a body is moving in X direction with a constant acceleration Alpha find the difference of the displacement by it n second and n-1 minus one second. ​

Answer 1

Answer:

distance in nth second = v0 + (α/2) (2n – 1) distance in (n – 1)th second = v0 + (α/2) [2(n – 1) – 1] = v0 + (α/2) (2n – 3) difference = [v0 + (α/2) (2n – 1)] – [v0 + (α/2) (2n – 3)] = (α/2) (2) = a