Question

A body is moving in X direction with constant acceleration alpha. Find the difference of the displacement covered by it in nth second and (n-1)th

Answer 1

Answer:

8 also have to be a 468 and you are right

Answer 2

Answer:

Explanation:

distance in nth second = v0 + (α/2) (2n – 1) distance in (n – 1)th

second = v0 + (α/2) [2(n – 1) – 1] = v0 + (α/2) (2n – 3)

difference = [v0 + (α/2) (2n – 1)] – [v0 + (α/2) (2n – 3)] =

(α/2) (2) =