A body is moving on a circle of radius 80m with a speed 20m/s which is decreasing at the rate of 5m/s2 at an istant. What is the angle made by its acceleration with its velocity?
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Answered by
13
Given: Radius(x) = 80m
Speed (u)= 20 m s-1
acceleration (a) = -5 m s-2
To find the angle made by its acceleration with its velocity
v = u +at
v = 20 + (-5)t
v = 20 -5t ........... (i)
v2 = u2 + 2as
v2 = (20)2 + 2(-5)s ...................(ii)
(20 - 5t)2 = 400 -10s
400 +25t2 - 200t = 400 - 10s
{25t (t - 8) }/ 10 = -s
-{25t (t - 8) }/ 10 = s ........................(iii)
Here "s" is the arc.
Angle = arc / radius
Angle = s / 80
Angle = -{25t (t - 8) / 10*80
Angle = (8-t) / 32
Speed (u)= 20 m s-1
acceleration (a) = -5 m s-2
To find the angle made by its acceleration with its velocity
v = u +at
v = 20 + (-5)t
v = 20 -5t ........... (i)
v2 = u2 + 2as
v2 = (20)2 + 2(-5)s ...................(ii)
(20 - 5t)2 = 400 -10s
400 +25t2 - 200t = 400 - 10s
{25t (t - 8) }/ 10 = -s
-{25t (t - 8) }/ 10 = s ........................(iii)
Here "s" is the arc.
Angle = arc / radius
Angle = s / 80
Angle = -{25t (t - 8) / 10*80
Angle = (8-t) / 32
Answered by
19
centripetal acceleration = 20*20/80 = 5 m/s2
tangential acceleration = 5 m/s2
so angle = tan-1(5/5) = 450
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