Question

A body is moving vertically upwards. Its
velocity changes at a constant rate from 50 m s-1 to
20 m s-1 in 3 s. What is its acceleration ?​

Answer 1

Answer:

Given:

Initial Velocity = 50 m/s

Final Velocity = 20 m/s

Time taken = 3 sec.

To find:

Acceleration of the body

Concept:

Acceleration refers to instantaneous change in velocity with respect to time . It's a vector Quantity having both directions and magnitude.

Calculation:

acc = \dfrac{change \: in \: velocity}{time}acc=

time

changeinvelocity

= > acc = \dfrac{20 - 50}{3}=>acc=

3

20−50

= > acc = \dfrac{ - 30}{3}=>acc=

3

−30

= > acc = - 10 \: m {s}^{ - 2}=>acc=−10ms

−2

So final answer :

\boxed{ \huge{ \red{ \bold{acc = - 10 \: m {s}^{ - 2} }}}}

acc=−10ms

−2

Important things to note :

Negative sign indicates opposite direction of acceleration as compared to velocity

It's also called Retardation or Deceleration.

Answer 2

Answer:

I have no answer.............

Explanation:

l hoLP help next time.