Physics, asked by rockstar619, 4 months ago

A body is moving with 15 m/s is accelerated at 4m/s^2 calculate distance travelled by body in 8 sec​

Answers

Answered by MehakThakran
1

Answer:

ANSWER

Given that,

The acceleration a=8m/s2

Initial velocity u=0m/s

We know that,

The displacement in the nth second

=u+a(n−21)

Now, the displacement in 5th second

  =0+8(5−21)

 =36m

Hence, the distance covered by it in fifth second is 36 m

Answered by Anonymous
0

Answer:

Given that,

The acceleration a=8m/s

2

Initial velocity u=0m/s

We know that,

The displacement in the nth second

=u+a(n−

2

1

)

Now, the displacement in 5th second

=0+8(5−

2

1

)

=36m

Hence, the distance covered by it in fifth second is 36 m

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