a body is moving with 20m/s find the required force to stop the body within 10 sec also calculate the distance travel bye the body in this duration given that mass of the body is 500 kg
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Given that,
- Velocity = 20 m/s
- Time = 10 sec
- Mass = 500 kg
- Acceleration = ?
- Force = ?
- Let's calculate the force,
F = ma ( Newton second law of motion )
[ We know a = v/t ]
F = mv/t
F = 500×20/10
F = 1000 N
- Let's calculate acceleration,
F = ma ( Newton second law of motion )
a = F/m
a = 1000/500
a = 2 m/s^2
- Distance covered by the body,
S = ut+1/2at^2
S = 20×10+1/2×2×10×10
S = 300 m
Hope this helps you.
Thank you for your question it had helped me to think.
Mark me as brainleist it took lot of time to solve this problem.
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