Question

a body is moving with a speed of 40 kilometre hour one second later it is moving at 58 kilometre hour what is it acceleration ​

Answer 1

u = 58km/h = (58×5)÷18

v = 40km/h = (40×5)÷18

a=( 5÷18)(18)= 5m/s*2

Answer 2

$\sf{\underline{Given:}}$

Initial speed (u) $\implies$ $\sf{40 \: km/h}$

$\implies$ $\sf{40 \times \frac{5}{18}}$

$\implies$ $\sf{ 40 \times 0.277777778}$

$\implies$ $\sf{11.1 \: m/s}$

Final speed (v) $\implies$ $\sf{ 58 \: km/h}$

$\implies$ $\sf{58 \times \frac{5}{18} }$

$\implies$ $\sf{58 \times 0.277777778}$

$\implies$ $\sf{ 16.11 \: m/s}$

Time (t) = $\sf{1\:sec}$

Acceleration (a) = ?

$\sf{\underline{We\:know\:that:}}$

$\boxed{\sf{a = \frac{(v - u)}{t}}}$

$\sf{\underline{By\:substituting\:the\:values,\:we\:get:}}$

$\implies$ $\sf{a = \frac{(v - u)}{t}}$

$\implies$ $\sf{a = \frac{(16.1 - 11.1)}{1}}$

$\implies$ $\sf{a = \frac{05.0}{1}}$

$\implies$ $\sf{a = 5 \: {m/s}^{2}}$

$\sf{\underline{Answer:}}$

Acceleration: $\sf{5\:m/s^{2}}$