Question

A body is moving with a speed of 5 m/s. In 5 sec the body comes to rest. Find acceleration and
distance covered by the body.​

Answer 1

Explanation:

u = 5m/s

v = 0m/s

t = 5 sec

using first equation of motion ,

v = u+at

0=5+a(5)

-5 = 5a

a = -5/5 => -1 m/s². ( negative sign denotes retardation of the a

body )

using second equation of motion,

s = ut+1/2at²

s = 5(5) + 1/2 × -1 × (5)²

s = 25+(-25/2)

s = [25(2) - 25]/2

s = (50-25)/2 => 25/2 m => 12.5 metres

hope this help

Answer 2

U = 5m/s , V = 0m/s

t = 5sec

a = (V - U)/t

= (0 - 5)/5

= -5/5

= -1m/s²

acceleration is negative so it is retardation

V² - U² = 2aS

0 - 25 = 2 * (-1) * S

-25 = -2 * S

25 = 2 * S

25/2 = S

12.5m

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