Question

A body is moving with a speed of 500m/s. a force acting on a mass 1×10^-2 kg opposes this motion. after 10 second the body fiads to be moving in opposite direction with same speed.find the force.

Answer 1

I hope you will understand

Answer 2

The force is acting on the body in opposite direction having magnitude of 1 N.

Explanation:

Given that,

Mass of the body, $m=10^{-2}\ kg$

Initial speed of the body, u = 500 m/s

Final speed of the body, v = -500 m/s (as it body fiads to be moving in opposite direction with same speed)

Time, t = 10 s

To find,

Force acting on the body.

Solution,

The force acting on the body is calculated by finding the product of mass and acceleration. It is given by :

$F=m\times a$

$F=\dfrac{m(v-u)}{t}$

$F=\dfrac{10^{-2}\times ((-500)-(500))}{10}$

F = -1 N

So, the force is acting on the body in opposite direction having magnitude of 1 N.

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