A body is moving with a uniform acceleration covers 40 m in the first 4 s and 120 m in next 4s. Its initial velocity and acceleration are
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given,
d1(distance)= 40m,. t1(time) = 4 s
therefore,
initial velocity = d1/ t1
= 40/4
= 10 m/s ans.....
given,
d2 (distance)= 120m , t2 (time) = 4 s
final velocity = 120 / 4
= 30m/s
therefore,
acceleration = (final velocity - initial velocity)/ time
= (30-10)/4
= 20/4
= 5 m/s2 answer...
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