A body is moving with a uniform acceleration covers 40m in the first 4s and 120m in the next 4s. Its initial velocity and acceleration are
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Answered by
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For first 4 seconds
S = ut + 0.5at²
40 = 4u + (0.5 × a × (4)²)
40 = 4u + 8a
Divide both sides by 4
10 = u + 2a …………[1]
For first 8 seconds
S = ut + 0.5at²
40 + 120 = 8u + (0.5 × a × (8)²)
160 = 8u + 32a
Divide both sides by 8
20 = u + 4a …………[2]
Subtract [2] from [1]
10 - 20 = u + 2a - u - 4a
-10 = -2a
a = 5 m/s²
Put a = 5 in [1]
10 = u + (2 × 5)
u = 0 m/s
∴ Initial velocity is zero and acceleration is 5 m/s²
S = ut + 0.5at²
40 = 4u + (0.5 × a × (4)²)
40 = 4u + 8a
Divide both sides by 4
10 = u + 2a …………[1]
For first 8 seconds
S = ut + 0.5at²
40 + 120 = 8u + (0.5 × a × (8)²)
160 = 8u + 32a
Divide both sides by 8
20 = u + 4a …………[2]
Subtract [2] from [1]
10 - 20 = u + 2a - u - 4a
-10 = -2a
a = 5 m/s²
Put a = 5 in [1]
10 = u + (2 × 5)
u = 0 m/s
∴ Initial velocity is zero and acceleration is 5 m/s²
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10
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