Question

A body is moving with a uniform speed vin a circular path of radius 7 as shown in figure. Tis period of revolution. The average velocity in
section AB is
B
o
27
T
4
T
4v
2.21​

Answer 1

Answer:

We know that v=Rω=R(2π/T)=(2πR/T)⟹(R/T)=(v/2π)

The average velocity of the particle for the semicircular path is V

av

=2R/(T/2)=4R/T

Substituting the value of R/T from previous equation, we get V

av

=4(v/2π)=2v/π

HOPE THIS HELPS.