Question

a body is moving with a unit acceleration of 10m/s^2. if its initial velocity is zero, calculate the displacement after 5s​

Answer 1

Answer:

The body travelled a distance of 125m during the 5s.

Explanation:

METHOD 1 -

Let’s review the 4 fundamental kinematic equations of motion for constant acceleration :

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 0, a = 10m/s^2, t = 5s and we want to find the distance traveled, s, so we use equation (1)

s = ut + ½at^2

s = 0 + 5(5^2) = 125

The body travelled a distance of 125m during the 5s.

METHOD 2 -

Starting from rest (v=0), if velocity increases by 10m/s each second then it will be 50m/s after 5 seconds,

Therefore, the average velocity was 25m/s for 5 seconds, so it will have traveled 125 m (assuming constant acceleration, no air resistance, no changes in mass, etc., etc.)

Hence, the body travels 125 m in 5 seconds.