Question

A body is moving with a velocity of 10 m / s. if
starts accelerating
with the rate of 2.5 m/s
find out its velocity after 10 s​

Answer 1

Given :

• InitiaI veIocity (u) = 10 m/s
• AcceIeration (a) = 2.5 m/s²
• Time (t) = 10 s

To find :

• FinaI veIocity of body

SoIution :

We have ;

→ u = 10 m/s

→ a = 2.5 m/s²

→ t = 10 s

Now using 1st equation of motion ;

⇒ v = u + at

Substituting vaIues :

⇒ v = 10 + 2.5 × 10

⇒ v = 10 + 25

⇒ v = 35

⇒ v = 35 m/s

∴ FinaI veIocity of body is 35 m/s

Equations of motion :

1. v = u + at
2. s = ut + 1/2 at²
3. v² - u² = 2as

Answer 2

$\mathcal{\gray{\underbrace{\blue{GIVEN:-}}}}$

• A body is moving with a velocity of 10m/s .

• It starts accelerating with the rate of 2.5m/s² .

$\mathcal{\gray{\underbrace{\blue{TO\: FIND:-}}}}$

• It's velocity after 10s .

$\mathcal{\gray{\underbrace{\blue{CALCULATION:-}}}}$

$\red\bigstar\:\mathcal{\pink{\boxed{\purple{v\:=\:u\:+\:at\:}}}}$

Where,

• v = final velocity = ?

• u = initial velocity = 10m/s .

• a = acceleration = 2.5m/s² .

• t = time = 10s .

$\rm{\implies\:v\:=\:10\:+\:2.5\times{10}\:}$

$\rm{\implies\:v\:=\:10\:+\:25\:}$

$\rm{\boxed{\green{\implies\:v\:=\:35\:m/s}}}$

$\rm\pink{\therefore}$ The velocity of the body after 10s is “35m/s” .

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MORE INFO :-

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⚡ Equation of Motion :-

✍️ When a body moving with constant acceleration, then we use the following Equation of Motion .

• $\rm{\pink{v\:=\:u\:+\:at\:}}$

• $\rm{\orange{v^2\:-\:u^2\:=\:2\:a\:s\:}}$

• $\rm{\green{s\:=\:ut\:+\:\dfrac{1}{2}\:at^2\:}}$