Question

 A body is moving with a velocity of 12m/s and it comes to rest after covering 18m.What was the acceleration?​


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Answer 1

Answer:

Explanation:

given,

u=12m/s

s=18m

v=0

now, by using 3rd equation of motion,

v^2=u^2+2as

0=(12)^2+2(a)(18)

=144+36a

-36a=144

a=144/-36

now, you can itself find out the answer.

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Answer 2

Answer:

-4m/s^2

Explanation:

Here v= final velocity. = 0

u= initial velocity. =12m/s

s=distance. =18m

Thus

v^2=u^2+2as

0=12^2+2 (18)a

0=144+36a

-144/36=a

-4m/s^2=acceleration