a body is moving with a velocity of 12m/ s and it comes to rest in 18 m, what was the acceleration?
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Using third law of motion here deceleration occurs
v*2-u*2=2as
Here v=0
So- (12)*2=2X(-a)X18
a=144/36
a=4mps*-2
v*2-u*2=2as
Here v=0
So- (12)*2=2X(-a)X18
a=144/36
a=4mps*-2
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this is the answer. hope it will help you.
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