Question

A body is moving with a velocity of 12m/s and it comes to rest in 18m, what was the acceleration

Answer 1

acc =-4m/s raise to power 2


u...12
v...0
s...18
2as=v*2-u*2



putting values gives us ans....

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Answer 2

Initial Velocity (u) = 12m/s
Final Velocity (v) = 0m/s
Distance Covered (s) = 18m
Acceleration (a) = a m/s^2

2as = v^2 - u^2 [second eq. of motion]
2(18)a = 0^2 - 12^2
36a = 0 - 144
36a = -144
a = -144/36 = -4

If acceleration = -4 m/s^2
Then,
Retardation or Deceleration = -(-4) = 4 m/s^2

Therefore, the body undergoes an acceleration of -4 m/s^2 or a retardation of 4 m/s^2.