Question

A body is moving with a velocity of 20 m/s. If the motion is uniform, what will be its velocity after 10 seconds?​

Answer 1

Answer:

Given -

Initial Velocity, u = 10m/s

Time, t = 10 sec

To find -

Velocity after 10 seconds.

Solution -

As per the Question, the body is in uniform motion, So, it's acceleration will be 0 m/s.

\begin{gathered} \\ \sf \: Acceleration = \dfrac{(v-u)}{t}\\ \\ \\ \implies \sf \:0 = \dfrac{(v - u)}{t} \\ \\ \\ \implies \sf \: 0 = \dfrac{(v - 10)}{10} \\ \\ \\ \implies \sf \: 0 \times 10 = v - 10 \\ \\ \\ \implies \sf \: 0 = v - 10 \\ \\ \\ \implies \sf{ \underline {\: 10 \: m \: per \: sec.}} \\ \\ \end{gathered}

Acceleration=

t

(v−u)

⟹0=

t

(v−u)

⟹0=

10

(v−10)

⟹0×10=v−10

⟹0=v−10

⟹

10mpersec.

Therefore, velocity after 10 sec will be 10 m/s.

Answer 2

${\mathfrak{{answer}}}$

A body is moving with a velocity of 10m/s. If the motion is uniform, what will be the velocity after 20sec?

The velocity of a moving object only changes of there is an acceleration.

Initial Velocity be u

Final Velocity be v

Here, it is given that motion is uniform.

So, v = u. →→→ (EQ.1)

If a is the acceleration,

a= v- u / t

From EQ.1 We know v = u.

a= v- u / t

a= 0 / t

a=0

∴a is 0 ms-²

If there is no acceleration, the velocity remains the same. So, after 20sec also the velocity is 10ms−¹

Note:

Acceleration here also refers to retardation or deceleration generally referred as negative acceleration. So don't get confused!

${\mathfrak{{☆ \:  I  \: hope \:  its  \: help  \: you \:  ☆}}}$