Question

A body is moving with a velocity of 4 m/ s and accelaration 2 m/s^2 .So find its velocity and distance travelled after 5 sec

Answer 1

u=4 m/s. t =5 sec. a= 2m/s². s= ? v=?
1.velocity.
v =u+at
v = 4 + 2×5
v = 14 m/s.
2.distance
s= ut+1/2 at²
s = 4×5 + 1/2×2×(5)²
s=45 m.
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Answer 2

Velocity after 5 seconds
v = u + at
= (4 m/s) + (2 m/s^2 × 5 s)
= 14 m/s
_________________

Distance travelled in 5 seconds
S = ut + 0.5at^2
= (4 m/s × 5 s) + [0.5 × 2 m/s^2 × (5 s)^2]
= 20 m + 25 m
= 45 m

[Note: For a body moving in straight line without changing its direction, distance is equal to displacement]