a body is moving with constant accerlation 5ms-2from A to B in straight line .The velocity of particle at A and B are 5 and 15 m/s .the velocity at mid point of AB is
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Given <br>
initial speed =5m/s<br>
final speed = 15m/s<br>
<br>
Starting from A<br>
u=5m/s<br>
v= speed at mid point=x(let)<br>
from third law of motion <br>
v^2-u^2=2as....(i)<br>
starting from mid point <br>
u'=speed at mid point =x<br>
v' = final speed <br>
from third law of motion <br>
v'^2-u'^2= 2as ....(ii)<br>
(since it is the mid point and it is in constant acceleration)<br>
From (i) and (ii)<br>
v^2-u^2=v'^2-u'^2<br>
=》x^2-25=225-x^2<br>
=》2x^2=250<br>
=》x^2=125<br>
=》 x=(125)^1/2<br>
<br>
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