Chemistry, asked by abnerkatiyar2005, 6 months ago

a body is moving with the velocity 2 metre per second and acceleration of 3 metre per second square calculate the velocity after it has travelled 77m​

Answers

Answered by prevanth1507
0

Hello,

The initial velocity = 2 m/sec

Uniform Acceleration = 3 m/sec²

Distance covered = 77m

From the equations of motion :-

We know that :-

2as = v²-u²

V² = 2as + u²

V² = 2*3*77+(2)²

V²=462+4=466

So,

Final velocity = root466 m/sec

Hope this will be helping you.......v

Answered by THELEGENDKINGDOM
0

Answer:

Explanation:

Hello,

The initial velocity = 2 m/sec

Uniform Acceleration = 3 m/sec²

Distance covered = 77m

From the equations of motion :-

We know that :-

2as = v²-u²

V² = 2as + u²

V² = 2*3*77+(2)²

V²=462+4=466

So,

Final velocity = root466 m/sec

Hope this will be helping you.......

Similar questions