a body is moving with the velocity 2 metre per second and acceleration of 3 metre per second square calculate the velocity after it has travelled 77m
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Answered by
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Hello,
The initial velocity = 2 m/sec
Uniform Acceleration = 3 m/sec²
Distance covered = 77m
From the equations of motion :-
We know that :-
2as = v²-u²
V² = 2as + u²
V² = 2*3*77+(2)²
V²=462+4=466
So,
Final velocity = root466 m/sec
Hope this will be helping you.......v
Answered by
0
Answer:
Explanation:
Hello,
The initial velocity = 2 m/sec
Uniform Acceleration = 3 m/sec²
Distance covered = 77m
From the equations of motion :-
We know that :-
2as = v²-u²
V² = 2as + u²
V² = 2*3*77+(2)²
V²=462+4=466
So,
Final velocity = root466 m/sec
Hope this will be helping you.......
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