Question

A body is moving with uniform acceleration reaches 108m and 140m in the 5th and 11th second respectively.And its initial velocity and acceleration​

Answer 1

Explanation:

$special \: equation \\ sn = u + \frac{a}{2} (2n - 1) \\ \\ 108m \: in \: 5th \: sec \\ sn = u + \frac{a}{2} (2n - 1) \\ 108 = u + \frac{a}{2} (2 \times 5 - 1) \\ 108 = u + \frac{9a}{2} \: \: \: \: eq1 \\ 140m \: in \: 11th \: sec \\ sn = u + \frac{a}{2} (2n - 1) \\ 140 = u + \frac{a}{2} (2 \times 11 - 1) \\ 140 = u + \frac{21a}{2} \: \: eq2$

after solving the 2 equation simultaneously we can get the answer

there fore

acceleration = 5.33 or 16/3

initial velocity= 84ms^-1